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A satellite of mass m revolves around the earth of radius R at a hight x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite isA. gxB. `(gR)/(R-x)`C. `(gR^(2))/(R+x)`D. `((gR^(2))/(R+x))^(1//2)` |
Answer» Correct Answer - D `(mv^(2))/(R+X)=(GM)/((R+X)^(2))=(gR^(2))/((R+X)^(2))` or `V=[(gR^(2))/(R+X)]^(1//2)` |
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