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A satellite orbiting around earth of radius R is shifted to an orbit of radius 2R. How many times the time taken for one revolution increase? |
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Answer» `2*5` times `T^(2)prop r^(3) therefore (T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3//2)` `T_(2)=T((2R)/(R ))^(3//2)` `RARR T_(2)=2sqrt(2)T=2xx1.41T=2.82T` Thus correct choice is (c ). |
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