A scooter weighing 150 kg together with its rider moving at 36 kin/hr

1.	A scooter weighing 150 kg together with its rider moving at 36 kin/hr is to take a turn of radius 30 in. What force on the scooter towards the center is needed to make the turn possible ? Who or what provides this?
Answer» Weight of the scooter with rider = 150 kg Speed = 36 km/hr = 36 × \(\frac{5}{18}\) = 10 m/sec. Radius of the turning = 30 m The force needed on the scooter towards the centre is centripetal force. Centripetal force F_c = \(\frac{mv^2}{r}=\frac{150\,\times\,10\,\times\,10}{30}\) = 500 N ∴ A centripetal force of 500 N is required on the car. This force is provided by the friction between the tyres of the car and road.

A scooter weighing 150 kg together with its rider moving at 36 kin/hr is to take a turn of radius 30 in. What force on the scooter towards the center is needed to make the turn possible ? Who or what provides this?

Answer»

Weight of the scooter with rider = 150 kg

Speed = 36 km/hr = 36 × \(\frac{5}{18}\) = 10 m/sec.

Radius of the turning = 30 m

The force needed on the scooter towards the centre is centripetal force.

Centripetal force F_c = \(\frac{mv^2}{r}=\frac{150\,\times\,10\,\times\,10}{30}\) = 500 N

∴ A centripetal force of 500 N is required on the car.

This force is provided by the friction between the tyres of the car and road.

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A scooter weighing 150 kg together with its rider moving at 36 kin/hr is to take a turn of radius 30 in. What force on the scooter towards the center is needed to make the turn possible ? Who or what provides this?

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