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A second order reaction in which both the reactants have same concentration , is 20% completed in 500 seconds . How much time it will take for 60% completion ? |
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Answer» SOLUTION :The second order EQUATION when both the REACTANTS have same CONCENTRATION is `k = 1/t .x/(a(a-x))` If a = 100, x20 , t = 500 seconds Then ` k =1/500xx(20)/(100xx(100-20))` When `a = 100,x = 60, t = ? ` `t = 1/ k . (60)/(100xx40)` Substituting the value of k , `t = (500xx100xx80)/(20)xx60/(100xx40)"or "t = 3000 ` seconds |
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