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A section of fixed smooth circular track of radius `R` in vertical plane is shown in the figure. A block is released from position `A` and leaves the track at `B` The radius of curvature of its trajectory just after it leaves the track `B` is ? A. RB. `( R)/(4)`C. `( R)/(2)`D. none of these |
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Answer» Correct Answer - C Apply conservation of energy with `O` as reference level `mg (2r)/(5) +0 = (mgr)/(5)+(1)/(2)mv^(2)` `v = sqrt((2gr)/(5))` , Radius of curvature `= (v_(1)^(2))/(a_(n))` `(2gr//5)/(g cos37) = (r)/(2)`. |
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