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A semicircular wire of radius R is oriented vertically. A small bead is released from rest at the top of the wire, it slides without friction under the influence of gravity to the bottom, where is then leaves the wire horizontally and falls a distance H to the ground. The bead lands a horizontal distance D away from where it was launched. Which of the following is a correct graph of RH against D^(2) ? |
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Answer»
`D=sqrt((2H)/(G))xxsqrt(4gR)=2sqrt(2RH)` `D^(2)=8RH` |
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