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A semiconductor has the electron concentration 0.45 xx 10^(12) m^(-3) and hole concentration 5 xx 10^(29) m^(-3) . Find its conductivity . Given electron mobility = 0.135 m^(2) V^(-1) s^(-1) and hole mobility = 0.048 m^(2) V^(-1) s^(-1) , e = 1.6 xx 10^(-19) C |
| Answer» SOLUTION :`3.845 OMEGA^(-1) m^(-1)` | |