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A series C–R circuit consists of a capacitance 16 mF and resistance 8Omega. If the input a.c. voltage is (200 V, 50 Hz), Calculate (i) voltage across capacitor and resistor. (ii) Phase by which voltage lags/leads current. |
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Answer» SOLUTION :Current in the circuit `I= (V)/(Z)` When `Z = sqrt(X_(C )^(2)+ R^2), X_(C ) = (1)/(omega C) = (1)/(2 PI v C)` Then TOTAL voltage across capacitor and resistor. `V_(C ) = I X_(C ), V_(R ) = IR`. (II) `tan phi = (X_C)/( R)` [ V lags current] |
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