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A series circuit contains a resistor of 20 Omega, a capacitor and an ammeter of negligible resistance. It is connected to a source of 200 V, 50 Hz. If the reading of ammeter is 2.5 A, calculate the reactance of the capacitor. |
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Answer» Solution :Here `R = 20 OMEGA, E_(RMS) = 200 V, v = 50 Hz, I_(rms) = 2.5 A` The circuit is CR circuit. Impedance of circuit. `Z_(CR) = (E_(rms))/(I_(rms)) = (200)/(2.5) = 80 Omega` But, `Z_(CR) = SQRT(R^(2) + X_(C)^(2))` or `X_(C)^(2) = Z_(CR)^(2) - R^(2)` or `X_(C)^(2)= sqrt(Z_(CR)^(2) - R^(2)) = sqrt((80)^(2) - (20)^(2)) = 77.46` ohm |
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