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A series circuit has an impedance of `60.0 Omega` and a power factor of `0.720` at `50.0 Hz`. The source voltage lags the current.(a) What circuit element, an inductor or a capacitor, should be placed in series with the circuit to raise its power factor?(b) What size element will raise the power factor to unity? |
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Answer» Correct Answer - A::B::C::D (a) Voltage lags `:. X_CgtX_L` Power factor, `cosphi=R/Z` `=R/(sqrt(R^2(X_C-X_L)^2)` To increase the power factor denominator should decrease. Hence `X_L` should increase. Therefore, an inductor is required to be connected. (b) `cosphi=R/Z=0.72` `:. R=0.72Z=0.72xx60` `=43.2Omega` `(X_C-X_L)=sqrt((60)^2-(43.2)^(2))` `=41.64Omega` New inductor of inductane `41.64Omega` should be added in the circuit. `L=X_L/(2pif)` `=41.64/(2pi(50))=0.133H`. |
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