InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A series combination of a coil of inductance L and a resistor of resistance 12Omega is connected across a 12 V, 50 Hz supply. Calculate L if the circuit current is 0.5 A. |
|
Answer» Solution :Impedance, `Z=(E)/(I)=(12)/(0.5)=24Omega` `and Z=sqrt(R^(2)+OMEGA^(2)L^(2))` `or Z^(2)=R^(2)+omega^(2)L^(2) or L^(2)=(Z^(2)-r^(2))/(omega^(2))` Here `omega=2piv=2xx(22)/(7)xx50` `="314 rads"^(-1) and R=12Omega` `L^(2)=((24)^(2)-(12)^(2))/((314)^(2)) or L=(12sqrt3)/(314)=0.066H` |
|