A series combination of `n_(1)` capacitors, each of value `C_(1)`, is charged by a source of potential difference `4 V`. When another parallel combination of `n_(2)` capacitors, each of value `C_(2)`, is charged by a source of potential difference `V`, it has same (total) energy stored in it, as the first combination has. the value of `C_(2)`, in terms of `C_(1)`, is thenA. `(2C_(1))/(n_(1)n_(2))`B. `16 (n_(2))/(n_(1))C_(1)`C. `2(n_(2))/(n_(1))C_(1)`D. `(16 C_(1))/(n_(1)n_(2))`

A series combination of `n_(1)` capacitors, each of value `C_(1)`, is

1.	A series combination of `n_(1)` capacitors, each of value `C_(1)`, is charged by a source of potential difference `4 V`. When another parallel combination of `n_(2)` capacitors, each of value `C_(2)`, is charged by a source of potential difference `V`, it has same (total) energy stored in it, as the first combination has. the value of `C_(2)`, in terms of `C_(1)`, is thenA. `(2C_(1))/(n_(1)n_(2))`B. `16 (n_(2))/(n_(1))C_(1)`C. `2(n_(2))/(n_(1))C_(1)`D. `(16 C_(1))/(n_(1)n_(2))`
Answer» Correct Answer - D Case I. When the capacitors are connected in series `U_("series") = (1)/(2) (C_(1))/(n_(1))(4V)^(2)` Case II. When the capacitors are connected in parallel `U_("parallel") = (1)/(2) (n_(2)C_(2)) V^(2)` According to question, `U_("series") = U_("parallel")` or `= (1)/(2)(C_(1))/(n_(1)) (4V)^(2) = (1)/(2) (n_(2)C_(2)) V^(2)` `rArr C_(2) = (16C_(1))/(n_(2)n_(1))`

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