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The work done in bringing a `20` coulomb charge from point `A` to point `B` for disatnce `0.2 m` is `2 J`. The potential difference between the two points will be (in volt)A. `0.2`B. `8`C. `0.1`D. `0.4` |
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Answer» Correct Answer - C By using `W = Q.DeltaV rArr DeltaV = (2)/(20) = 0.1` volt |
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