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If the potential of a capacitor having capacity of `6 muF` is increased from 10 V to 20 V,then increase in its energy will beA. `12 xx 10^(-6) J`B. `9 xx 10^(-4) J`C. `4 xx 10^(-6) J`D. `4 xx 10^(-9) J` |
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Answer» Correct Answer - B The increase in energy of the capacitor `DeltaU = (1)/(2) C(V_(2)^(2) - V_(1)^(2)) = (1)/(2) (6 xx 10^(-6)) (20^(2) - 10^(2))` `= 3 xx 10^(-6) xx 300 = 9 xx 10^(-4) J` |
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