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A series LCR a.c. circuit has L = 2.0 H, C = 32 μF and R = 10 Omega. (a) At what angular frequency of a.c. will it resonate ? (b) Calculate the Q value of the circuit. |
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Answer» Solution :Here L = 2.0 H, C = 32 μF =`32xx10^(-6)F`, and R=10`OMEGA` (a) `therefore` RESONANT angular frequency `omega_(r)=1/(SQRT(LC))=1/(Sqrt(LC))=1/(sqrt(2.0xx32xx10^(-6)))=125rads^(-1)` (b) The Q-value of the circuit=`(Lomega_(r))/R=(2.0xx125)/10=25` |
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