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A series LCR circuit contains a pure inductor of inductance 5.0H, a capacitor of capacitance 20mu F and a resistor 40Omega. Find the resonant frequency of the circuit. Calculate the quality factor (Q- factor ) of the circuit. What is the impedance at resonant condition? |
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Answer» Solution :`L= 5H, C= 20 XX 10^(6)F, R= 40 Omega` Resonant FREQUENCY `f_(0)= (1)/(2pi sqrt(LC))` `f_(0)= (1)/(2 xx 3.14 sqrt(5 xx 20 xx 10^(-6)))` `f_(0)= 15.91 Hz or 16Hz` `Q= (1)/(R )sqrt((L)/(C ))= (1)/(40) sqrt((5)/(20 xx 10^(-6))) = 12.5` Impedance at resonant Z= R `Z= 40Omega` |
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