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A series LCR circuit is connected to a 220 V ac source of variable frequency . The inductance of the coil is 5 H, capacitance of the capacitor is 5muF and resistance is 40 Omega . At resonance , calculate current in the circuit . |
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Answer» SOLUTION :`I=V/Z` at RESONANCE Z=R= `40Omega` `I=(22cancel0)/(4cancel0)`=5.5A I=5.5 A |
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