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A series LCR circuit is connected to a 220 V ac source of variable frequency . The inductance of the coil is 5 H, capacitance of the capacitor is 5muF and resistance is 40 Omega . At resonance , calculate The resonant frequency . |
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Answer» Solution :GIVEN: V=220V L=5H `C=5HF=5xx10^(-6)F` `R=40Omega` At RESONANCE XL =XC `V_0=1/(2pisqrt(LC))=1/(2xx3.142sqrt(5xx5xx10^(-6)))` `=1/(2xx3.142sqrt(5xx5xx10^(-6)))=1/(6.2884xx5xx10^(-3))` `=1/(31.42xx10^(-3))=0.0318xx10^3` `V_0`=31.81 Hz |
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