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A series LCR circuit is connected to an a.c. source of variable frequency. Drow a suitable phasor diagram deduce the expressions for the amplitude of the current and phase angle. |
Answer» Solution : From the phasor diagram `vec(V) = SQRT((V_(RM))^(2) + (V_(CM) - V_(LM))^(2))` `V_(m) = sqrt([R^(2) + (X_(C) - X_(L))^(2)])` `I_(m) = (V_(m))/(sqrt([R^(2) + (X_(C) - X_(L))^(2)])` From the figure `tan phi = (V_(Cm) - V_(Lm))/(V_(Rm))` `= (I_(m)(X_(C) - X_(L)))/(I_(m)R)` `:. phi = tan^(-) ((X_(C) - X_(L))/(R ))` |
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