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A series `R-L-C` circuit has `R = 100 Ohm. L = 0.2 mH` and `C = (1)/(2) mu F`. The applied voltage `V = 20 sin omega t`. When the current lags the applied voltage by `45^(@)`, the equation of the current isA. `0.2 sin (omega t + tan^(-1) 0.3)`B. `0.2 sin (omega t - tan^(-1) 0.3)`C. `0.3 sin (omega t + tan^(-1) 0.3)`D. `0.3 sin (omega t - tan^(-1) 0.3)`

Answer» Correct Answer - B


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