

InterviewSolution
Saved Bookmarks
1. |
A series resonant LCR circuit has a quality factor (Q-factor)=0.4. If `R=2k Omega, C=0.1 mu F` then the value of inductance isA. `0.1 H`B. `0.064 H`C. 2 HD. 5 H |
Answer» Correct Answer - B Quality factor `Q = (1)/(R )sqrt((L)/(C ))` or `(L)/(C )=(QR)^(2)` Here, `Q = 0.4, R = 2 k Omega= 2xx10^(3)Omega` `C=0.1 mu F=0.1xx10^(-6)F` `therefore L=(QR)^(2)C` `therefore L =(0.4xx2xx10^(-3))^(2)xx0.1xx10^(-6)=0.064 H` |
|