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A shaft initially rotating at 1725 rpm is brought to rest uniformly in 20s. The number of revolutions that the shaft will make during this time isA. 1680B. 575C. 287D. 627 |
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Answer» `0=omega_(0)-alphat` `thereforealpha=(omega_(0))/(t)=((2pi)(1725//60))/(20)` `=9rad//s^(2)` `theta=(1)/(2)alphat^(2)=(1)/(2)xx9xx(20)^(2)=1800rad` `N=(theta)/(2pi)=287` |
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