A shell is fired from a canon with a velocity theta at angle with the horizontal direction. At the highest point in its path it explodes into two pieces of equal masses. One of the pieces retraces its path to the canon. The speed of the other piece immediately after the explosion is:

A shell is fired from a canon with a velocity theta at angle with the

1.	A shell is fired from a canon with a velocity theta at angle with the horizontal direction. At the highest point in its path it explodes into two pieces of equal masses. One of the pieces retraces its path to the canon. The speed of the other piece immediately after the explosion is:
Answer» 3V COS `theta` 2v cos `theta` `3/2` v`theta` v cos`theta` Solution :Applying CONSERVATION law `m_1v_1+m_2v_2=mv cos theta` Now `m_1=m_2=m/2` and `v_1=-v cos theta` `m/2(-v cos theta)+m/2v_2=mv cos theta` or`v_2=3v cos theta`.

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A shell is fired from a canon with a velocity theta at angle with the horizontal direction. At the highest point in its path it explodes into two pieces of equal masses. One of the pieces retraces its path to the canon. The speed of the other piece immediately after the explosion is:

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