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A shell of mass 2 kg and moving at a rate of 4 m/s suddenly explodes into two equal fragments. Thefragments go in directions inclined with the original line of motion with equal velocities. If the explosion imparts 48 J of translational kinetic energy to the fragments divided equally, the velocity (magnitude and direction both) of each fragment :- |
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Answer» 2 m/s , `45^@` 2 kg x 4m/s = 1kg x v cos `theta` m/s+1 kg x v cos `theta` m/s  `8 = 2v cos theta` `v cos theta` = 4 m/s ….(i) The initial kinetic energy of the shell `=1/2xx2kgxx(4m//s)^2` =16 J An amount of 48 J is imparted by EXPLOSION. Thus, the total energy of the fragments is 64 J, i.e. each fragment has 32 J kinetic energy `=1/2xx 1kg xx v^2 `=32 J `v^2`=64 v=8m/s and `v cos theta `=4 `cos theta =1/2 RARR theta =60^@` |
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