A shopkeeper bought two units of an article at the same price. He sold

1.	A shopkeeper bought two units of an article at the same price. He sold one unit at a profit of 30%. If on selling the second unit, he incurred a loss which was one-third of the profit earned on the first unit, what was his overall profit percent ?1). 16%2). 12%3). 8%4). 5%
Answer» Solution Let COST price of each unit = Rs. $100x$ => C.P. of both units = $2 \times 100x = 200x$ Profit % on 1st unit = 30% => S.P. of one unit = $\frac{130}{100} \times 100x = 130x$ => Profit earned on FIRST unit = Rs. $(130x - 100x) = 30x$ Now, loss incurred is one-third of the profit => Loss incurred on second unit = Rs. $\frac{30x}{3} = 10x$ => S.P. of second unit = Rs. $(100x - 10x) = 90x$ Thus, total S.P. of both units = $130x + 90x = 220x$ $\therefore$ OVERALL profit % = $\frac{220x - 200x}{200x} \times 100$ = $\frac{20}{2} = 10 \%$

A shopkeeper bought two units of an article at the same price. He sold one unit at a profit of 30%. If on selling the second unit, he incurred a loss which was one-third of the profit earned on the first unit, what was his overall profit percent ?1). 16%2). 12%3). 8%4). 5%

Answer»

Solution

Let COST price of each unit = Rs. $100x$

=> C.P. of both units = $2 \times 100x = 200x$

Profit % on 1st unit = 30%

=> S.P. of one unit = $\frac{130}{100} \times 100x = 130x$

=> Profit earned on FIRST unit = Rs. $(130x - 100x) = 30x$

Now, loss incurred is one-third of the profit

=> Loss incurred on second unit = Rs. $\frac{30x}{3} = 10x$

=> S.P. of second unit = Rs. $(100x - 10x) = 90x$

Thus, total S.P. of both units = $130x + 90x = 220x$

$\therefore$ OVERALL profit % = $\frac{220x - 200x}{200x} \times 100$

= $\frac{20}{2} = 10 \%$

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