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A shopkeeper has a certain number of apples of which 10% are found to be rotten. He sells 85% of the remaining good apples and still has 405 good apples left with him. How many apples did he originally have?1. 35002. 30003. 25004. 2000 |
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Answer» Correct Answer - Option 2 : 3000 Given: Rotten apples = 10% Remaining sold good apples = 85% good apples = 405 Calculation: let he had originally be X apples. According to the question: ∴ Rotten apples = (X × 10%) =10X/100 ⇒ Rotten apples = X/10 Again, sold apples = 85% 0f (X – X/10) ⇒ [(85/100) × (9X/10)] = 153X/200 Now, (X/10 + 153X/200 + 405) = X ⇒ (20X + 153X + 81000)/200 = X ⇒ 173X + 81000 = 200X ⇒ 200X – 173X = 81000 ⇒ 27X = 81000 ⇒ X = 81000/27 ⇒ X = 3000 ∴ He originally had 3000 apples. |
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