1.

A shopkeeper has a certain number of apples of which 10% are found to be rotten. He sells 85% of the remaining good apples and still has 405 good apples left with him. How many apples did he originally have?1. 35002. 30003. 25004. 2000

Answer» Correct Answer - Option 2 : 3000

Given: 

Rotten apples = 10%

Remaining sold good apples = 85%

good apples = 405

Calculation:

let he had originally be X apples.

According to the question:

∴ Rotten apples = (X × 10%) =10X/100

⇒ Rotten apples = X/10

Again,

sold apples = 85% 0f (X – X/10)

⇒ [(85/100) × (9X/10)] = 153X/200

Now,

(X/10 + 153X/200 + 405) = X

⇒ (20X + 153X + 81000)/200 = X

⇒ 173X + 81000 = 200X

⇒ 200X – 173X = 81000

⇒ 27X = 81000

⇒ X = 81000/27

⇒ X = 3000

∴ He originally had 3000 apples.



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