A shopkeeper sold first unit of an article to Aria at 20% discount and

1.	A shopkeeper sold first unit of an article to Aria at 20% discount and the second unit of the same article at 40% discount. If the shopkeeper earned an overall profit of 5%, the marked price of the article was what percent of the cost price of the article ?1). 2002). 1503). 1254). 160
Answer» Solution Let the cost price of each article = RS. $100x$ => C.P. of both articles = $2 \TIMES 100x = 200x$ => Selling price = $\frac{105}{100} \times 200x = 210x$ ------------------EQN(1) Let the marked price = Rs. $100y$ Selling price of 1st article after 20% discount = $\frac{80}{100} \times 100y = 80y$ Selling price of 2nd article after 40% discount = $\frac{60}{100} \times 100y = 60y$ => Total selling price = $80y + 60y = 140y$ --------------------Eqn(2) Comparing eqns(1) & (2), we get : => $210x = 140y$ => $\frac{y}{x} = \frac{210}{140} = \frac{3}{2}$ $\therefore$ Required % = $\frac{3}{2} \times 100 = 150 \%$

A shopkeeper sold first unit of an article to Aria at 20% discount and the second unit of the same article at 40% discount. If the shopkeeper earned an overall profit of 5%, the marked price of the article was what percent of the cost price of the article ?1). 2002). 1503). 1254). 160

Answer»

Solution

Let the cost price of each article = RS. $100x$

=> C.P. of both articles = $2 \TIMES 100x = 200x$

=> Selling price = $\frac{105}{100} \times 200x = 210x$ ------------------EQN(1)

Let the marked price = Rs. $100y$

Selling price of 1st article after 20% discount = $\frac{80}{100} \times 100y = 80y$

Selling price of 2nd article after 40% discount = $\frac{60}{100} \times 100y = 60y$

=> Total selling price = $80y + 60y = 140y$ --------------------Eqn(2)

Comparing eqns(1) & (2), we get :

=> $210x = 140y$

=> $\frac{y}{x} = \frac{210}{140} = \frac{3}{2}$

$\therefore$ Required % = $\frac{3}{2} \times 100 = 150 \%$

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