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A short bar magnet o magnetic field . It experiences a torque of 0.05 J. Calculate the magnitude of the magnetic field. |
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Answer» Solution :Theposition of minimum energy corresponds to position of STABLE equilibrium The energy `(upsilon) = - mB cos THETA ` when `theta = 0^(@) , upsilon = - MU B ` = minimum energyHence when the bar MAGNET is placed parallel to the MAGNETIC field , it is the state of stable equilibrium. |
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