InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A short bar magnet of magnetic moment m=0.32 JT^(-1) is placed in a uniform magnetic field of 0.15 T. If the bar is free to rotate in the place of the field , which orientation would correspond to its (a) stable , and (b) unstable equilibrium ? What is the potential energy of the magnet in each case ? |
|
Answer» Solution :`m=0.32JT^(-1),b = 0.15T` a. The bar MAGNET is directed ALONG the direction of external field so that PE is MINIMUM , `U = - mB = -4.8 xx10^(-2)J` (most stable ) b. Any other position , other than the above is UNSTABLE. The one with maximum PE is with the field antiparallel to that of the magnet . In this case. `U_(max)=mB=4.8xx10^(-2)J` |
|