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A short bar magnet placed with its axis at `30^(@)` with an external field of 800 G experiences a torque of 0.016 Nm. The bar magnet is replaced by a solenoid of cross-sectional area `2 xx 10^(-4) m^(2)` and 1000 turns, but of the same magnetic moment. Determine the current flowing through the solenoid. |
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Answer» From Eq. `m_(s) = NIA`. From part (a), `m_(s) = 0.40 A m^(2)` `0.40 = 1000 xx 1 xx 2 xx 10^(-4)` `I = 0.40 xx 10^(4)//(1000 xx 2) = 2A` |
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