1.

A short linear object of length l lies along the axis of a concave mirror of focal length f at a distance u from the pole of mirror. The size of image is nearly equal to

Answer»

`l (U + F)^(2))`
`l (u - f^(2))`
`l((f)/(u - f))^(2)`
`l((u-f)/(f))^(2)`

Solution :(c ) Longitudinal SIZE, du = l, dv = ? `therefore "magnification" (V)/(u) = ((f)/(u-f))`
From eqn. (1), Longitudinal size of IMAGE,
`dv = ((f)/(u-f))^(2) . L`


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