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| 1. |
A short magnet is placed with its magnetic axis on the magnetic meridian, with its N-pole facing north. A neutral point is found on the perpendicular bisector at 10cm from the centre of the magnet. If B_H =0.4 xx 10^(-4) T, then find the magnetic moment of the magnet? |
| Answer» SOLUTION :`0.4 Am^(2)` | |