A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(t). The resulting signal is passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be :(a) Impulse(b) m(t)(c) 0(d) m(t)del(t)The question was posed to me in homework.I'm obligated to ask this question of Spectrum Analysis of Sampling Process topic in chapter Digital Control Systems of Control Systems

A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(

1.	A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(t). The resulting signal is passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be :(a) Impulse(b) m(t)(c) 0(d) m(t)del(t)The question was posed to me in homework.I'm obligated to ask this question of Spectrum Analysis of Sampling Process topic in chapter Digital Control Systems of Control Systems
Answer» CORRECT answer is (c) 0 The EXPLANATION is: m (t) G (t)->M (f)*G (f) After low pass filtering with FC =1 kHz, hence the output is zero.

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