1.

A signature, written in carbon pencil weighs 1 mg. what is the number of carbon atoms present in the signature?

Answer»

`5.02xx10^(23)`
`5.02xx10^(20)`
`6.02xx10^(20)`
`0.502xx10^(20)`

SOLUTION :1MG=`1xx10^(-3)g`
`because` 12g carbon CONTAINS=`6.023xx10^(23)` carbon
atoms
`therefore1xx10^(-3)` g carbon contains
`=(6.023xx10^(23))/(12)xx1xx10^(-3)`
`=0.502xx10^(20)` carbon atoms.


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