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A silver wire has a resistance of 2.1 Omega at 27.5^(@) C and a resistance of 2.8 Omega at 100^(@) C . Determine the temperature coefficient of resistivity of silver. |
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Answer» SOLUTION :Here `R_(1) = 2.1 Omega,"" R_(2) = 2.7 Omega` `t_(1) = 27.5^(@) C, t_(2) = 100^(@)C ` `ALPHA = ? ` `R_(2) = R_(1) [ 1 + alpha (t_(2) - t_(1)) ] ` `therefore (R_(2))/(R_(1)) = 1 +alpha [ t_(2) - t_(1)]` `therefore (R_(2) - R_(1))/(R_(1))= alpha [ t_(2) - t_(1)]` `thereforealpha = (R_(2) - R_(1))/(R_(1) [t_(2) - t_(1)] )` ` = (2.7 - 2. 1)/(2.1(100- 27.5))` `= (0.6)/(2.1 XX 72.5)` = 0.00394 `= 0.0039^(@)C^(-1)` |
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