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A silver wire has a resistance of 2.1 Omegaat 27.5^@C,and a resistance of 2.7 Omega at 100^@C . Determinethe temperature coefficient of resistivity of silver. |
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Answer» SOLUTION :Here `T_1 =27.5^@C , R_1 = 2.1 Omega , T_2 = 100^@C and R_2 = 2.7 Omega` From the relation `R_2 = R_1 [1+ ALPHA (T_2- T-1) ]` , we have TEMPERATURE coefficient of resistivity of SILVER `alpha = (R_2 - R_1)/(R(T_2 - T_1)) = (2.7 - 2.1)/(2 (100 - 27.5) ) = (0.6)/(2.1 xx 72.5) = 0.0039^@C^(-1)` |
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