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A simple harmonic oscillator has amplitude A, angular velocity `omega`, and mass m . Then, average energy in one time period will beA. `(1)/(4)m omega^(2)A^(2)`B. `(1)/(2)m omega^(2)A^(2)`C. `m omega^(2)A^(2)`D. zero |
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Answer» Correct Answer - A Average energy `=(int_(0)^(T)"u dt")/(int_(0)^(T)dt)=(1)/(T)int_(0)^(T)"u dt"` `=(1)/(2T)int_(0)^(T)momega^(2)A^(2)cos^(2)(omegat+phi)dt=(1)/(4)momega^(2)A^(2)` |
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