1.

A simple pendulum executing S.H.M. is falling freely along with the support. ThenA. it does not oscillate at allB. its periodic time increaseC. its periodic time decreaseD. None of the above

Answer» Correct Answer - A
(a) Time period of a simple pendulum,
`T=2pisqrt((l)/(g))`
For freely falling effective , g=0
So, `T=oo`
`therefore` Pendulum does not oscillate at all.


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