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A simple pendulum executing S.H.M. is falling freely along with the support. ThenA. it does not oscillate at allB. its periodic time increaseC. its periodic time decreaseD. None of the above |
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Answer» Correct Answer - A (a) Time period of a simple pendulum, `T=2pisqrt((l)/(g))` For freely falling effective , g=0 So, `T=oo` `therefore` Pendulum does not oscillate at all. |
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