1.

A simple pendulum has a pariod T inside a lift when it is stationary. The lift is accelerated upwards with constant acceleration 'a'. The period :

Answer»

DECREASES
increases
remains same
SOMETIMES increases and sometimes decreases.

Solution :When the lift ascends with acceleration a then apparent value of acceleration due to gravity BECOMES `(g+a)`
As `T=2pi sqrt((l)/(g))`.
So the TIME PERIOD decreases.
Hence correct choiceis (a).


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