1.

A simple pendulum is executing simple harmonic motion with a time period T. If thelength of pendulumis increased by 21 %, the % increase in the time period of the pendulum of increased length is :

Answer»

0.1
0.21
0.3
0.5

Solution :Here `""(T_(2))/(T_(1))=SQRT((121)/(100))=(11)/(10)`
`:.""T_(2)=(11)/(10)T_(1)`
%INCREASE in time PERIOD `=(T_(2)-T_(1))/(T_(1))XX100`
`=((11)/(10)T_(1)-T_(1))/(T_(1))xx100=10%`.
Correct choice is (a).


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