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A simple pendulum is made by attaching `1Kg` bob to `5m` long copper wire of diameter `0.08cm` and it has a certatin period of oscillation and `10kg bob` is replaced by `kg bb` the change in time period is `(Y = 12.4xx10^(10) Nm^(-2))`A. `0.0035 sec`B. `4.4915 sec`C. `4.488 sec`D. `0.0021 sec` |
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Answer» Correct Answer - A `T_(1) = 2pi sqrt((l + Delta l_(1))/(g))` and `T_(2) = 2pi sqrt((l + Delta l_(2))/(g)),Delta T = T_(2) - T_(1)` |
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