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A simple pendulum of length 1 m the bob performs circular motion in horizontal plane if its string making an angle ` 60 ^(@)` with the verticle , then the period of rotation of the bob will be `(g=10 m//s^(2)`A. `2 s`B. `1.4 s`C. `1,98 s`D. `4 s` |
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Answer» Correct Answer - B `T=2pi sqrt((l cos theta)/(g))` `=2pi sqrt((1xx cos 60)/(10))` `=2pisqrt((1)/(2)xx(1)/(10))=sqrt2=1.48`. |
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