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A simple pendulum of length 1 m with a bob of mass m swings with an angular amplitude 30°. Then (g = 9.8 ms^(-2)) |
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Answer» time period of pendulum is 2 s  Simle pendulum of LENGTH 1 m is CALLED second.s pendulum whose time period is T =2S. But this time period is for small oscillations. In this case, angular amplitude is `30^(@)`. Therefore, time period wil not be 2s. At angular displacement `15^(@)`. `T-mg cos 15^(@) =(mv^(2))/l` or `T gt mg cos 15^(@)` and tangential acceleration `a = g sin 15^(@)` = rate of change of speed. |
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