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A simple pendulum of length l is suspended from the ceilling of a car moving with a speed v on a circular horizontal road of radius r. a. Find the tension in the string when it is at rest with respect to the car. b.Find the time period of small oscillation. |
Answer» Correct Answer - `2pisqrt(l/((g^2+v^4)/r^2)^(1/2))` a. From the free body diagram `T=sqrt((mg)^2+((mv^2)/r)^2)` `=m sqrt((g^2+v^4)/r^2)` `=msqrt((g^2+v^4)/r^2)=ma` where a=acceleration `a=((g^2+v^4)/r^2)^(1/2)` The time period of small acceleration is given by `T=2pisqrt(l/a)` `=2pisqrt(l/((g^2+v^4)/r^2)^(1/2))` |
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