1.

A simple pendulum oscillates in a verticle plane. When it passes through the mean position,the tension in the string is 3 times the weight of the pendulum bob. What is the maximum angular displacement of the pendulum of the string with respect to the vertical ?

Answer»

`30^(@)`
`60^(@)`
`45^(@)`
`90^(@)`

Solution :At lowest pt. `T-mg=(mv^(2))/(l)impliesT=mg+(mv^(2))/(l)`
`:.""mg+(mv^(2))/(l)=3mg""implies""v=sqrt(2GL)`
`:.` Velocity will be ZERO when it is at vertical height l i.e., whenthe string makes an angle of `90^(@)`withvertical.
`:.` CORRECT choice is (d).


Discussion

No Comment Found

Related InterviewSolutions