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A simple pendulum oscillates with an amplitude of 2xx10^(-2)m. If the force acting on it at extreme position is 4 N. Then the time that another simple pendulum of length 81 cm takes to execute the same number of oscillations is |
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Answer» 4N `=((A)/(2))/(A)=(1)/(2)` `F_(m)=(F_(e))/(2)=(4)/(2)=2N` |
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