1.

A simple pendulum oscillates with an amplitude of 2xx10^(-2)m. If the force acting on it at extreme position is 4 N. Then the time that another simple pendulum of length 81 cm takes to execute the same number of oscillations is

Answer»

4N
3N
2N
1N

Solution :`(F_(m))/(F_(e))=(kx_(m))/(kx_(e))`
`=((A)/(2))/(A)=(1)/(2)`
`F_(m)=(F_(e))/(2)=(4)/(2)=2N`


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