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A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle `2 theta`. The earth’s magnetic field component in the direction perpendicular to swing is B . Maximum potential difference induced across the pendulum is A. `2BL sin ((theta)/(2)) (gL)^(1//2)`B. `BL sin ((theta)/(2)) (gL)`C. `BL sin ((theta)/(2)) (gL)^(3//2)`D. `BL sin ((theta)/(2)) (gL)^(2)` |
| Answer» Correct Answer - A | |