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A single electron orbits around a stationary nucleus of charge +Ze, where Z is a constant and e is the magnitude of the electronic charge. It requires 47.2eV to excite the electron from second Bohr orbit to the third bar Bohr orbit. Find : (a) the value of Z, (b) the energy required to excite the electron from n=3 to n=4. |
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Answer» Solution :(a) Transition is `n_(1) =2 to n_(2) =3, E= 47.2eV`. we have `DELTA E = 13.6Z^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))EV` `rArr 47.2 =13.6Z^(2) ((1)/(2^2)-(1)/(3^2)) rArr Z=5`. (B) transition is `n_(1) =3 to n_(2) =4, E =?` we have `Delta E =13.6Z^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))eV` `Delta E =13.6 xx (5^2)((1)/(3^2)-(1)/(4^2))=16.53eV`. |
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