InterviewSolution
Saved Bookmarks
| 1. |
A single slit of width a is illuminated by violet light of wavelength `400nm` and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength `600nm`, the width of the diffraction pattern is |
|
Answer» Correct Answer - C Given, `lambda_(1)=4000 nm, lambda_(2)=600 nm, d_(1)=d and d_(2)=(d)/(2)` In single slit diffraction experiment, width of central maxima `y=(2lambdaD)/(d) rArr (y_(1))/(y_(2))=(lambda_(1))/(lambda_(2))xx(d_(2))/(d_(1))` `therefore (y_(1))/(y_(2))=(400)/(600)xx((d)/(2))/(d)=(1)/(3)` So, `y_(2)=3y_(1)=3y` |
|