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A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which `R = 3 Omega. L = 25.48mH`. And `C = 796mu F`. The impedance of the circuit

Answer» To find the impedance of the circuit, we first calculate `X_(L)` and `X_(C )`.
`X_(L)=2pi vL`
`= 2xx3.14xx50xx25.48xx10^(-3)Omega=8Omega`
`X_(C )=(1)/(2pivC)`
`= (1)/(2xx3.14xx50xx796xx10^(-6))=4Omega`
Therefore,
`z=sqrt(R^(2)+(X_(L)-X_(C ))^(2))=sqrt(3^(2)+(8-4)^(2))`


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